2cos^2x+sin(3x)=2

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Solution for 2cos^2x+sin(3x)=2 equation:


Simplifying
2cos2x + sin(3x) = 2

Remove parenthesis around (3x)
2cos2x + ins * 3x = 2

Reorder the terms for easier multiplication:
2cos2x + 3ins * x = 2

Multiply ins * x
2cos2x + 3insx = 2

Solving
2cos2x + 3insx = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3insx' to each side of the equation.
2cos2x + 3insx + -3insx = 2 + -3insx

Combine like terms: 3insx + -3insx = 0
2cos2x + 0 = 2 + -3insx
2cos2x = 2 + -3insx

Divide each side by '2os2x'.
c = o-1s-2x-1 + -1.5ino-1s-1

Simplifying
c = o-1s-2x-1 + -1.5ino-1s-1

Reorder the terms:
c = -1.5ino-1s-1 + o-1s-2x-1

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